The tallest Sequoia sempervirens tree in California's Redwood National Park is 111 m tall. Suppose an object is thrown downward from the top of that tree with a certain initial velocity. If the object reaches the ground in 3.80 seconds, what is the objects initial velocity?
I don't know what formula to use on this. Please help?Help with Physics math!?
0=111+vo(3.8)+-4.9(3.8)^2 and solve
x=xo+vo(t)+ 1/2at^2
u know
x=0
xo=111
vo=??
v doesnt matter
a=-9.8
t=3.8
solveHelp with Physics math!?
s=ut+1/2at^2
111=ux3.8+1/2x-9.8 x 3.8^2
111=3.8u-4.9x14.44
3.8u=111-70.756
u=40.244/3.8
u=10.59m/s
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