H= V0t + 0.5 g t^2
V0 =( H - 0.5 g t^2)/t
V0= (111 - 0.5 x 9.81 (3.80)^2)/ 3.80
V0=10.6 m/sec
S=ut+(1/2)at^2
Where S=111
u=initial velocity
a=9.8
t=3.80
plugnchugPhysics problem?
9.4 m/s
Friday, March 9, 2012
Physics problem?
The tallest Sequoia sempervirens tree in California's Redwood National park is 111 m tall. Suppose an object is thrown downward from the top of that tree with a certain initial velocity. If that object reaches the ground in 3.80 s, what is the object's initial velocity?Physics problem?
H= V0t + 0.5 g t^2
V0 =( H - 0.5 g t^2)/t
V0= (111 - 0.5 x 9.81 (3.80)^2)/ 3.80
V0=10.6 m/sec
S=ut+(1/2)at^2
Where S=111
u=initial velocity
a=9.8
t=3.80
plugnchugPhysics problem?
9.4 m/schrome download acura rsx
H= V0t + 0.5 g t^2
V0 =( H - 0.5 g t^2)/t
V0= (111 - 0.5 x 9.81 (3.80)^2)/ 3.80
V0=10.6 m/sec
S=ut+(1/2)at^2
Where S=111
u=initial velocity
a=9.8
t=3.80
plugnchugPhysics problem?
9.4 m/s
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